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Ring Strain in Cyclopropane
The Lack of Ring Strain in Cyclohexane
The Large Ring Strain in Cyclopropane
 
  - Unlike acyclic hydrocarbons, cyclic hydrocarbons may have 
    strain which is inherent in their cyclic structures. This is called RING 
    STRAIN. 
 
  - Ring Strain consists primarily 
    of two diffferent kinds of strain: (1)torsional strain and (2)angle 
    strain.Torsional strain, of course, arises when bonds are not ideally 
    staggered. In most ring systems, it is impossible to perfectly stagger all 
    bonds. In cyclohexane, fortuitously, perfect bond staggering occurs in the 
    chair conformation, but no conformation in any other ring allows for such 
    perfect staggering.  
 
  - ANGLE STRAIN arises when the C-C-C bonds of the ring 
    depart (because of geometric necessity) from the ideal tetrahedral angle preferred 
    for sp3 carbon. Again, in chair cyclohexane this angle just happens to be 
    virtually identical to the tetrahedral angle, so that neither angle nor torsional 
    strain occurs in cyclohexane in the chair form. Therefore the total ring 
    strain is nil for cyclohexane. 
  
  - Cyclopropane, the smallest 
    cycloalkane, is rather highly strained (although it is still easily isolated 
    and stored). The estimated total ring strain in cyclopropane is 28 kcal/mol 
    (from heats of combustion measurements). When this value is compared with 
    the strength of a typical C-C bond (ca. 88 kcal/mol), it can be seen 
    that ring strain substantially weakens the C-C bonds of the ring. Hence, 
    cyclopropane is much more reactive than acyclic alkanes and other cycloalkanes 
    such as cyclohexane and cyclopentane. 
  
  - The carbon framework of cyclopropane is planar, by definition.That 
    is , it could not be otherwise, because it takes three points to define a 
    plane, and the positions of the three carbon nuclei define these points. Thus, 
    there is essentially no conformational analysis required for cyclopropane. 
    You might recall that we had earlier pointed out the strain in planar cyclohexane 
    is large, because all of the C-C bonds are eclipsed when the carbon 
    framework is planar. This is also true in cyclopropane, or in any other planar 
    conformation of a cycloalkane. Thus, planar conformations are usually disfavored, 
    but no other conformation is available to cyclopropane. Since there are three 
    C-C bonds in cyclopropane, and each of them is staggered, we can estimate 
    that there is at least 3X3 = 9 kcal/mol of torsional strain in cyclopropane. 
    
  
  - Since the total ring strain in cyclopropane is about 28 
    kcal/mol, it is evident that the major part of the ring strain must arise 
    from another factor. This is angle strain. Angle strain in cyclopropane 
    arises from the circumstance that the C-C-C angle is forced to be 60 degrees 
    (that of an equilateral triangle), about 49 degrees less than the ideal angle 
    for the strongest C-C bond (the strain angle is ca. 49 degrees. 
  
  - Looking at this in a little more detail, we can see that 
    the C-C bonds of cyclopropane are "bent" and not pure 
    sigma bonds. Recall that overlap is greatest when orbitals overlap "end-on", 
    i.e., via sigma bonding. Pi bonds overlap laterally. The overlap in cyclopropane 
    is neither end-on or lateral, but in between. So it is intermediate between 
    sigma and pi bonding. These bonds are also sometimes called "banana 
    bonds". 
  
  - The cause of the bent overlap is that the internuclear 
    angle ( the angle between the bond lines connecting the nuclei) is forced 
    to be much smaller (60 degrees) than the interorbital angle (the angle 
    between the axis of the two AO's on a given carbon), which is 109.5 degrees. 
 
  
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